document.write( "Question 26569: The sum of two numbers is 90. The second is 10 more than 4 times the first. What are the two numbers?\r
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Algebra.Com's Answer #14440 by Earlsdon(6294)\"\" \"About 
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Let the two numbers be a and b.\r
\n" ); document.write( "\n" ); document.write( "\"The sum of two numbers (a+b) is (=) 90. The second (b) is 10 more (+10) than 4 times the first (4a)\" So b = 4a+10 Puting it all together , you have:\r
\n" ); document.write( "\n" ); document.write( "\"a+%2B+b+=+90\"
\n" ); document.write( "\"a+%2B+4a%2B10+=+90\" Simplify and solve for a.
\n" ); document.write( "\"5a+%2B+10+=+90\" Subtract 10 from both sides.
\n" ); document.write( "\"5a+=+80\" Divide both sides by 5.
\n" ); document.write( "\"a+=+16\"\r
\n" ); document.write( "\n" ); document.write( "\"b+=+4a%2B10\"
\n" ); document.write( "\"b+=+4%2816%29%2B10\"
\n" ); document.write( "\"b+=+64%2B10\"
\n" ); document.write( "\"b+=+74\"\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "The two numbers are: 16 and 74
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