document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192355>Question 192355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log5 square root of 125 - log2 square root of 2= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144393 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> basic  form  is  log  base  a  of  b = ( log b)/(loga)\r<BR>\n" );
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document.write( "log  base 5  of  sq rt 125 -  log base  2  of  sq rt 2\r<BR>\n" );
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document.write( "log  of  neg  number  is  undefined  therefore  only  use  positive  sq  rts\r<BR>\n" );
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document.write( "(log sq  rt  125 / log 5 )   -(log  sq  rt  2/ log 2)<BR>\n" );
document.write( "(log  11.18/log5) - (log 1.414/log2)<BR>\n" );
document.write( "1.5-.5<BR>\n" );
document.write( "1.0 </SPAN>\n" );
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