document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192333>Question 192333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If someone could answer this with an explanation as to how they did it. I would be very grateful.\r<BR>\n" );
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document.write( "Sabrina met a really good-looking guy at a dance recently. She wanted to know how old he was so she asked him. He was a bit of a trickster at heart so he said, \" The larger of two numbers is 1 less than 3 times the smaller. their sum is 63. If you can find the smaller you will know my age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144373 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The larger of two numbers is 1 less than 3 times the smaller. their sum is 63.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "x + y = 63<BR>\n" );
document.write( "x = 3y-1<BR>\n" );
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document.write( "Substitute to solve for \"y\":<BR>\n" );
document.write( "3y-1 + y = 63<BR>\n" );
document.write( "4y = 64<BR>\n" );
document.write( "y = 16 (the smaller of the two numbers)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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