document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26563>Question 26563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For f(x) = 2x – 11, find f(2) I really cannot comprehend how to do this, can you please explain? Thanks :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14434 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you have f(x) = 2x -11 and are asked to find f(2), all you have to do is substitute the 2 from f(2) for x in the given function f(x).\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%282%29+=+2%282%29+-+11 ALIGN=MIDDLE  ALT=\"f%282%29+=+2%282%29+-+11\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%282%29+=+-7 ALIGN=MIDDLE  ALT=\"f%282%29+=+-7\"   DISABLED_style= \"max-width:90%; height:auto;\" >...and that's all there is to it! </SPAN>\n" );
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