document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192298>Question 192298</A>: <I><SPAN STYLE=\"word-break: break-all;\"> divide 5x^3-5x+1 by x-3<BR>\n" );
document.write( "explain what i am doing<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144334 by </B><A HREF=/tutors/aboutme.mpl?userid=Tieria.Erde><B>Tieria.Erde(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Tieria.Erde><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144334\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     5x^2-15x+45+46/x-3<BR>\n" );
document.write( "    _________<BR>\n" );
document.write( "x-3|5x^3+0x^2-5x+1<BR>\n" );
document.write( "  - 5x^3-15x^2 <BR>\n" );
document.write( "        -15x^2-5x<BR>\n" );
document.write( "        -15x^2+45x<BR>\n" );
document.write( "               45x+1<BR>\n" );
document.write( "              -45x+45<BR>\n" );
document.write( "                   (46)^\r<BR>\n" );
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document.write( "You basically the same thing as in regular division. Except since it's missing the x^2 you have to add it. and keep going on.. on the last part since this problem has a remainder you have to add it on to your answer but you have to include the x-3 on the denominator of 46.\r<BR>\n" );
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document.write( "5x^2-15x+45+46<BR>\n" );
document.write( "            x-3 </SPAN>\n" );
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