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You can put this solution on YOUR website!
I am having difficulty with linear rgression. I could sure use some help with my problems. At the very end is what I have so far. Thanks in advance for all your help.
\n" ); document.write( "The data below are the gestation periods, in months, of randomly selected animals and their corresponding life spans, in years.
\n" ); document.write( "Gestation, x: 8, 2.1, 1.3, 1, 11.5, 5.3, 3.8, 24.3
\n" ); document.write( "Life span, y: 30, 12, 6, 3, 25, 12, 10, 40
\n" ); document.write( "n= 8
\n" ); document.write( "A. find the equation of the regression line for the given data. round the line values to the nearest two decimal points.
\n" ); document.write( "y = 1.52x + 6.34
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\n" ); document.write( "B. using the equation found in part a, predict the life span when the gestation is 10 months. Round to the nearest absence.
\n" ); document.write( "f(10) = 1.52*10 + 6.34
\n" ); document.write( "f(10) = 15.2 + 6.34
\n" ); document.write( "f(10) = 21.54
\n" ); document.write( "------------------------------
\n" ); document.write( "Guidlines -- Hypothesis testing steps:
\n" ); document.write( "1. State Ho and Ha
\n" ); document.write( "2. Specify the level of significance alpha a
\n" ); document.write( "3. Find the standarized test statistic t = r / sqrt [1 - r squared] [n-2]
\n" ); document.write( "4. Find the criticalvalue(s) to. Use the method specified in the problem statement.
\n" ); document.write( "5. Define the rejection region using critical value(s).
\n" ); document.write( "6. Make a decision to reject or fail to rejct the null hypothesis.
\n" ); document.write( "7. Interpret the decision in the context of the original claim.
\n" ); document.write( "I think Ho and Ha are: Ho: p = 0 and Ha: p does not equal 0, which would make this a 2 tail
\n" ); document.write( "This is what I have:
\n" ); document.write( "X Y X * Y X² Y²
\n" ); document.write( "8 30 240 64 900
\n" ); document.write( "2.1 12 25.2 4.41 144
\n" ); document.write( "1.3 6 7.8 1.69 36
\n" ); document.write( "1 3 3 1 9
\n" ); document.write( "11.5 25 287.5 132.25 625
\n" ); document.write( "5.3 12 63.6 28.09 144
\n" ); document.write( "3.8 10 38 14.44 100
\n" ); document.write( "24.3 40 972 590.49 1600
\n" ); document.write( "∑x═ ∑y═ ∑xy═ ∑x²═ ∑y²═
\n" ); document.write( "57.3 138 1637.1 836.37 3558
\n" ); document.write( "n = 8 d.f = 8 - 2 = 6 (-3.707, 3.707) {two-tailed test} cu = ±3.707; Reject Ho if t < -3.707 or t > 3.707
\n" ); document.write( "r = 0.915931364 cv = 0.917
\n" ); document.write( "Strong positive correlation because \"r\" is close to 1 \r
\n" ); document.write( "\n" ); document.write( "8 (1637.1) - (57.3) (138) = 5189.4 {13096.8 - 7907.4}
\n" ); document.write( "8 (836.37) - (57.3)² = 3407.67 {6690.96 - 3283.29}
\n" ); document.write( "8 (3558) - (138)² = 9420 {28464 - 19044}
\n" ); document.write( "5189.4 / sqrt [3407.67] [9420] = 0.9159313639 or 0.916 (rounded to 3 decimal places) \r
\n" ); document.write( "\n" ); document.write( "t= 0.916 / sqrt 1-(0.916)² / 8-2
\n" ); document.write( "sqrt (1-(.916)²) = 0.4011782646 / sqrt (8-2) = 0.1637803407
\n" ); document.write( ".916 / 0.1637803407 = 5.59286 or 5.593 (rounded to 3 decimal places) \r
\n" ); document.write( "\n" ); document.write( "Because t is in the rejection region, you should decide to reject the null hypothesis.
\n" ); document.write( "There is enough evidence to conclude that a significant linear correlation exists. \r
\n" ); document.write( "\n" ); document.write( "------------------------------------------------
\n" ); document.write( "I have not checked your work below # 7.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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