document.write( "Question 192253This question is from textbook Intermediate Algeba
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document.write( ": To Solve Integer problems: \r
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document.write( "The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers. \r
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document.write( "my try:
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document.write( "First integer: 3n
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document.write( "Second integer: 8n-3 \r
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document.write( "3n + 8n-3 = 10
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document.write( "11n -3 =10
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document.write( "11n = 13
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document.write( "n = 13/11 \r
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document.write( "Not right? \r
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document.write( "Help!
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Algebra.Com's Answer #144287 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers. \n" ); document.write( "my try: \n" ); document.write( "First integer: 3n \n" ); document.write( "Second integer: 8n-3 \n" ); document.write( "3n + 8n-3 = 10 \n" ); document.write( "11n -3 =10 \n" ); document.write( "11n = 13 \n" ); document.write( "n = 13/11 \n" ); document.write( "Not right? \n" ); document.write( "Help! \n" ); document.write( "------------ \n" ); document.write( "Not much chance it's right since it's not an integer. \n" ); document.write( "smaller integer = s \n" ); document.write( "bigger integer = b \n" ); document.write( "3b+3 = 8s \n" ); document.write( "b+s = 10 --> s = 10-b \n" ); document.write( "Sub for s into 1st eqn \n" ); document.write( "3b+3 = 8*(10-b) \n" ); document.write( "3b+3 = 80-8b \n" ); document.write( "11b = 77 \n" ); document.write( "b = 7 \n" ); document.write( "s = 3 \n" ); document.write( " \n" ); document.write( " |