document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192188>Question 192188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with the following problem:<BR>\n" );
document.write( "(x+5)/(x-2)>_ (the previous sign is greater than or equal to) 0\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144257 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+5)/(x-2)>=0<BR>\n" );
document.write( "x cannot be 2 because there would be division by zero, so 2 is an inflection point.<BR>\n" );
document.write( "Let (x+5)/(x-2)=0 <BR>\n" );
document.write( "x+5=0 multiply each side by x-2<BR>\n" );
document.write( "x=-5 another inflection point is -5.<BR>\n" );
document.write( "Now we test points on either side of the inflection points to see if the equation is >=0<BR>\n" );
document.write( "Let x=-6: (-6+5)/(-6-2)>=0 true<BR>\n" );
document.write( "Let x=-4: (-4+5)/(-4-2)>=0 false<BR>\n" );
document.write( "Let x=3: (3+5)/(3-2)>=0 true<BR>\n" );
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document.write( "x(infinity, -5] U (2, infinity) answer.<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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