document.write( "Question 192209: 2log4-log3+logx-4=0 \n" ); document.write( "

Algebra.Com's Answer #144252 by nerdybill(7384) $\"\"$ $\"About$

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2log4-log3+logx-4=0
\n" ); document.write( "log4^2-log3+logx-4=0
\n" ); document.write( "log(4^2/3)+logx-4=0
\n" ); document.write( "log(16/3)+logx-4=0
\n" ); document.write( "log(16(x-4)/3)=0
\n" ); document.write( "16(x-4)/3 = 10^0
\n" ); document.write( "16(x-4)/3 = 1
\n" ); document.write( "16(x-4) = 3
\n" ); document.write( "x-4 = 3/16
\n" ); document.write( "x = 3/16 + 4
\n" ); document.write( "x = 3/16 + 64/16
\n" ); document.write( "x = 67/16
\n" ); document.write( " \n" ); document.write( "

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