document.write( "Question 192195: Please help me with this algebra 2 problem.\r
\n" ); document.write( "\n" ); document.write( "Directions: Using inverses simplify the expression.
\n" ); document.write( "#48:5^log x
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\n" ); document.write( "I dont exactly know how to type that but its 5 raised to log is followed by a small 5 thats a little bit lower and next to that a little raised is an x.\r
\n" ); document.write( "\n" ); document.write( "I have no idea how to do that but i know that the answer is x could you please explain this to me?
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Algebra.Com's Answer #144248 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "What you meant was:\r
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\n" ); document.write( "\n" ); document.write( "And here is how you would render such a thing as an input to this site:\r
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\n" ); document.write( "\n" ); document.write( "5^(log(5,(x)))\r
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\n" ); document.write( "\n" ); document.write( "Now, for the solution to your problem. Remember that:\r
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\n" ); document.write( "\n" ); document.write( "But notice that in your problem, you are raising 5 to a base-5 logarithm. What means is \"the number I would use as an exponent on 5 to equal x\" Hence if you raise 5 to the power of the number you would use as an exponent on 5 to equal x, then you would just get x.\r
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