document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192182>Question 192182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve...\r<BR>\n" );
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document.write( "A women has $7000,part is invested for one year paying 7% interest and the remaining amount in a fund paying 9%. After a year total interest on the 2 investments is $540. How much is invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144224 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let amounts invested at 7% and 9% be x and y respectively<BR>\n" );
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document.write( "x+y=7000...........eq 1<BR>\n" );
document.write( ".07x+.09y=540......eq 2<BR>\n" );
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document.write( "rewrite eq 1 to x=7000-y and plug this into eq 2<BR>\n" );
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document.write( ".07(7000-y)+.09y=540<BR>\n" );
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document.write( "490-.07y+.09y=540<BR>\n" );
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document.write( ".02y=50<BR>\n" );
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document.write( "y=2500 dollars invested at 9%<BR>\n" );
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document.write( "x=7000-y=7000-2500=4500 dollars invested at 7% </SPAN>\n" );
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