document.write( "Question 26546: A Farm is divided into 3 regions. The area of one region is twice as large as the area of the smallest region, and the area of the third region is 4 acres less than 3 times the area of the smallest region. Total acreage is 512 acres. Find the area of each of the 3 regions. \n" ); document.write( "
Algebra.Com's Answer #14419 by Paul(988)\"\" \"About 
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Let the smallest region be x
\n" ); document.write( "Let the one region be 2x
\n" ); document.write( "LEt the third region be 3x-4
\n" ); document.write( "Total = 512
\n" ); document.write( "x+2x+3x-4=512
\n" ); document.write( "6x-4=512
\n" ); document.write( "6x=516
\n" ); document.write( "x=86\r
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\n" ); document.write( "\n" ); document.write( "2(86)=172
\n" ); document.write( "3(86)-4=254\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, the smallest region is 86 acres, the second region is 172 acres and the third region is 254 acres.
\n" ); document.write( "PAul.
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