document.write( "Question 192008This question is from textbook Elementary and intermediate algebra
\n" ); document.write( ": Junior’s boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9miles upstream then what is the speed of the current \n" ); document.write( "
Algebra.Com's Answer #144180 by ankor@dixie-net.com(22740)\"\" \"About 
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Junior’s boat will go 15 miles per hour in still water. If he can go 12 miles
\n" ); document.write( " downstream in the same amount of time as it takes to go 9 miles upstream then
\n" ); document.write( "what is the speed of the current.
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\n" ); document.write( "Let c = speed of the current
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\n" ); document.write( "(15+c) = speed downstream
\n" ); document.write( "and
\n" ); document.write( "(15-c) = speed upstream
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\n" ); document.write( "Write a time equation; Time = \"distance%2Fspeed\"
\n" ); document.write( "Time down = time up
\n" ); document.write( "\"12%2F%28%2815%2Bc%29%29\" = \"9%2F%28%2815-c%29%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "9(15+c) = 12(15-c)
\n" ); document.write( "135 + 9c = 180 - 12c
\n" ); document.write( "9c + 12c = 180 - 135
\n" ); document.write( "21c = 45
\n" ); document.write( "c = 2.143 mph is the speed of the current
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\n" ); document.write( "Check solution by finding the times using a calc:
\n" ); document.write( "\"12%2F%28%2815%2B2.143%29%29\" = 7.0
\n" ); document.write( "\"9%2F%28%2815-2.143%29%29\" = 7.0 hrs\r
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