document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26541>Question 26541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by elimination  Please help I don't understand what to do<BR>\n" );
document.write( "1.  7x/2+7y/3=77/3<BR>\n" );
document.write( "     x/4+y/3=8/3         these are fractions   7x over 2 + 7y over 3 = seventy-seven over three\r<BR>\n" );
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document.write( "2.   3 squared x-y=2<BR>\n" );
document.write( "     6x+y=9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14417 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st: Multiply through  the first equation by 6 to get:<BR>\n" );
document.write( "  21x+14y=154<BR>\n" );
document.write( "Multiply through the second equation by 12 to get:<BR>\n" );
document.write( "  3x+4y=32<BR>\n" );
document.write( "Now, let say you want to eliminate the \"x\" terms.<BR>\n" );
document.write( "Multiply through the new 2nd equation by -7 to get:<BR>\n" );
document.write( "-21x-28y=-224<BR>\n" );
document.write( "Add this to the new 2nd equation to get:<BR>\n" );
document.write( "0x-14y=-70<BR>\n" );
document.write( "Divide by -14 to get y=5<BR>\n" );
document.write( "Substitute that into 3x+4y=32 to solve for \"x\", as follows:<BR>\n" );
document.write( "3x+4(5)=32<BR>\n" );
document.write( "3x=12<BR>\n" );
document.write( " x=4<BR>\n" );
document.write( "solution for the system of equations is x=4 and y=5<BR>\n" );
document.write( "Check that in the equation 21x+14y=154\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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