document.write( "Question 192107: Suppose a population of initial size 100 grows at the rate of 8% per year forever.
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document.write( "What is the size of the population at the end of year 1?
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document.write( "What is the size of the population at the end of year 2?
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document.write( "What is the size of the population at the end of year 3?
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document.write( "What is the size of the population at the end of year n (for any integer n)?
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document.write( "What algebraic equation would you need to solve to find the number of years x that it would take for our population to reach 200? \n" );
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Algebra.Com's Answer #144145 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! A=P(1+r)^t\r \n" ); document.write( "\n" ); document.write( "1) A(1) = 100(1.08)^1= 108 \n" ); document.write( "2) A(2)= 100(1.08)^2=116.64 \n" ); document.write( "3) A(3)= 100(1.08)^3=125.97 \n" ); document.write( "4) A(n)=100(1.08)^n \n" ); document.write( "5) 200=100(1.08)^n \n" ); document.write( "divide both sides by 100 \n" ); document.write( "2=(1.08)^n\r \n" ); document.write( "\n" ); document.write( "log both sides\r \n" ); document.write( "\n" ); document.write( "log2 =log (1.08)^n=n*log(1.08)\r \n" ); document.write( "\n" ); document.write( "divide both sides by log(1.08) and simplify\r \n" ); document.write( "\n" ); document.write( "(log(2))/(log(1.08))= 9.006=n\r \n" ); document.write( "\n" ); document.write( "check \n" ); document.write( "200=100log(1.08)^9.006= 200 ok \n" ); document.write( " |