document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192099>Question 192099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 55-gallon barrel contains a mixture with a concentration of 30%. How much of this mixture must be withdrawn and replaced by 100% concentrate to bring the mixture up to 50% concentrate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144143 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144143\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> total is  55  gal\r<BR>\n" );
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document.write( "at  30%,  solute  is  30% 0f 55  or  .3*55=  16.5  gal\r<BR>\n" );
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document.write( "required  to  have  50%  of  55  =  .50*55=  27.5  gal\r<BR>\n" );
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document.write( "16.5  -  .3x  +1.00x  = 27.5\r<BR>\n" );
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document.write( "subt  16.5  both  sides  and  simplify\r<BR>\n" );
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document.write( "(1-.3)x= 11\r<BR>\n" );
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document.write( ".7x  = 11\r<BR>\n" );
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document.write( "divide  by  .7\r<BR>\n" );
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document.write( "x=15.714    or  in  sig  fig  (16)   ANSWER\r<BR>\n" );
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document.write( "checking<BR>\n" );
document.write( ".3*15.714 =  4.714\r<BR>\n" );
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document.write( "16.5 - 4.714+15.714 = 27.5     ok </SPAN>\n" );
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