document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26508>Question 26508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you simplify the following:\r<BR>\n" );
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document.write( "1.  3rd order radical of 432x^8 (instead of square root it is the cube root)\r<BR>\n" );
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document.write( "2. Solve:  Square Root (2x+6)= 2 Square Root x\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14414 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> #1 (432*8)^(1/3)= 8^(1/3)[8*27]^(1/3)=8^(1/3)*8^(1/3)*7^(1/3)=2*2*3=12<BR>\n" );
document.write( "#2 sqrt(2x+6)=2sqrt(x)<BR>\n" );
document.write( "Square both sides to get:<BR>\n" );
document.write( "2x+6=4(x)<BR>\n" );
document.write( "Subtract 2x from both sides to get:<BR>\n" );
document.write( "2x=6<BR>\n" );
document.write( "Divide by \"2\" to get:<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
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