document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192069>Question 192069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.How many mililiters of a 20% acid solution should Annie mix with a 60% acid solution to make 100 mililiters of a 50% acid solution?\r<BR>\n" );
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document.write( "Smeagol kicked a ball. The function h(t)= -16t2 +80t describes the height of the ball, in feet, t seconds<BR>\n" );
document.write( "after he kicked it. How many seconds did the ball take to first reach 64 feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144133 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x and y be the amount of 20% and 60% solutions<BR>\n" );
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document.write( "x+y=100......eq 1<BR>\n" );
document.write( ".2x+.6y=.5(100)...eq 2<BR>\n" );
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document.write( "rewrite eq 1 to x=100-y and plug it into eq 2<BR>\n" );
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document.write( ".2(100-y)+.6y=50<BR>\n" );
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document.write( "20-.2y+.6y=50<BR>\n" );
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document.write( ".4y=30<BR>\n" );
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document.write( "y=75 mililiters of 60% solution<BR>\n" );
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document.write( "x=100-y=100-75=25 milliliters of 20% solution </SPAN>\n" );
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