document.write( "Question 192034: the perimeter of a rectangle is 68 ft. The lenght is 2 ft less than 3 times the width. Please help me find the lenght and width. \n" ); document.write( "
Algebra.Com's Answer #144132 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! P=68........eq 1 \n" ); document.write( "L=3W-2......eq 2 \n" ); document.write( "P=2L+2W.....eq 3 \n" ); document.write( ": \n" ); document.write( "take L's value and P's value from eq 1 and 2 and plug them into eq 3 \n" ); document.write( ": \n" ); document.write( "68=2(3W-2)+2W \n" ); document.write( ": \n" ); document.write( "68=6W-4+2W \n" ); document.write( ": \n" ); document.write( "8W=72 \n" ); document.write( ": \n" ); document.write( "W=9 feet \n" ); document.write( ": \n" ); document.write( "L=3(9)-2=25 feet \n" ); document.write( " |