document.write( "Question 192034: the perimeter of a rectangle is 68 ft. The lenght is 2 ft less than 3 times the width. Please help me find the lenght and width. \n" ); document.write( "
Algebra.Com's Answer #144132 by Mathtut(3670)\"\" \"About 
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P=68........eq 1
\n" ); document.write( "L=3W-2......eq 2
\n" ); document.write( "P=2L+2W.....eq 3
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\n" ); document.write( "take L's value and P's value from eq 1 and 2 and plug them into eq 3
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\n" ); document.write( "68=2(3W-2)+2W
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\n" ); document.write( "68=6W-4+2W
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\n" ); document.write( "8W=72
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\n" ); document.write( "W=9 feet
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\n" ); document.write( "L=3(9)-2=25 feet
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