document.write( "Question 192065This question is from textbook Saxon Algebra 2
\n" ); document.write( ": Find a8 of a geometric sequence given that a3 = 32 and a5 = 512. \n" ); document.write( "
Algebra.Com's Answer #144125 by nerdybill(7384)\"\" \"About 
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\n" ); document.write( "http://www.regentsprep.org/Regents/math/algtrig/ATP2/GeoSeq.htm
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\n" ); document.write( "An = A1(r^(n-1))
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\n" ); document.write( "The idea is that because they gave you:
\n" ); document.write( "a3 = 32 and a5 = 512
\n" ); document.write( "you can now find A1(first term) and r (the common ratio).
\n" ); document.write( "Now, you can find any term after that.
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\n" ); document.write( "An = A1(r^(n-1))
\n" ); document.write( "32 = A1(r^2)
\n" ); document.write( "A1 = 32/r^2
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\n" ); document.write( "An = A1(r^(n-1))
\n" ); document.write( "An = A1(r^4)
\n" ); document.write( "512 = (32/r^2)(r^4)
\n" ); document.write( "512 = 32(r^2)
\n" ); document.write( "16 = r^2
\n" ); document.write( "4 = r (common ratio)
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\n" ); document.write( "A1 = 32/r^2 = 32/4^2 = 32/16 = 2 (first term)
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\n" ); document.write( "An = A1(r^(n-1))
\n" ); document.write( "a8 = (2)(4^(8-1))
\n" ); document.write( "a8 = (2)(4^7)
\n" ); document.write( "a8 = 2*16384
\n" ); document.write( "a8 = 32768 \n" ); document.write( "
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