document.write( "Question 192073: Find the exact vertex of the parabola algebraically...\r
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\n" ); document.write( "\n" ); document.write( "f(x) = (x - 1)^2 + (x + 3) \r
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\n" ); document.write( "\n" ); document.write( "Could you please provide a detailed explantion of how you achieved the solution. Thanks!
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Algebra.Com's Answer #144121 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
The \"vertex form\" is
\n" ); document.write( "y= a(x-h)2+k
\n" ); document.write( "where
\n" ); document.write( "(h,k) is the vertex
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\n" ); document.write( "The idea is to make your equation look like that:
\n" ); document.write( "f(x) = (x - 1)^2 + (x + 3)
\n" ); document.write( "f(x) = (x - 1)(x - 1) + (x + 3)
\n" ); document.write( "f(x) = x^2 - 2x + 1 + x + 3
\n" ); document.write( "f(x) = x^2 - x + 4
\n" ); document.write( "Group x-terms:
\n" ); document.write( "f(x) = (x^2 - x) + 4
\n" ); document.write( "Complete the square:
\n" ); document.write( "f(x) = (x^2 - x + __ ) + 4
\n" ); document.write( "f(x) = (x^2 - x + 1/4 ) + 4 -1/4
\n" ); document.write( "f(x) = (x - 1/2)^2 + 16/4 -1/4
\n" ); document.write( "f(x) = (x - 1/2)^2 + 15/4
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\n" ); document.write( "vertex = (1/2, 15/4)
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