document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192043>Question 192043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this problem<BR>\n" );
document.write( "population p grows according to the equation dp/dt=kp where k is a constant and t is measured in years. if the population doubles every 12 years then the value of k is approximately<BR>\n" );
document.write( "a) 3.585<BR>\n" );
document.write( "b)1.792<BR>\n" );
document.write( "c)0.693<BR>\n" );
document.write( "d)0.729<BR>\n" );
document.write( "e)0.058<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144111 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> take dp/dt=kp  and solve for p to get p = Ae^(kt) (it's a solution to given DE)\r<BR>\n" );
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document.write( "2A = Ae^(k*12)\r<BR>\n" );
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document.write( "2 = e^(12k)\r<BR>\n" );
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document.write( "ln(2) = 12k\r<BR>\n" );
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document.write( "Ans: k = ln(2)/12\r<BR>\n" );
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document.write( "k ~ 0.05776\r<BR>\n" );
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document.write( "Answer is e)\r<BR>\n" );
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