document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191964>Question 191964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> subtract\r<BR>\n" );
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document.write( "(x^2-2x-3)/(x^2-9x+18) - (x^2-5x-6)/(x^2+9x+8)\r<BR>\n" );
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document.write( "it is two fractions and (x^2-2x-3) is the numerator of the first fraction and (x^2-5x-6) is the numerator of the second fraction\r<BR>\n" );
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document.write( "thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144064 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x^2-2x-3)/(x^2-9x+18) - (x^2-5x-6)/(x^2+9x+8)<BR>\n" );
document.write( "(X-3)(X+1)/(X-6)(X-3)-(X-6)(X+1)/(X+8)(X+1)<BR>\n" );
document.write( "CANCEL OUT THE (X-3) TERMS IN THE FIRST FRACTION & THE (X+1) IN THE SECOND FRACTION.<BR>\n" );
document.write( "(X+1)/(X-6)-(X-6)/(X+8)<BR>\n" );
document.write( "[(X+1)(X+8)-(X-6)(X-6)]/[(X-6)(X+8)]<BR>\n" );
document.write( "[X^2+9X+8-(X^2-12X+36)]/(X-6)(X+8)<BR>\n" );
document.write( "(X^2+9X+8-X^2+12X-36)/(X-6)(X+8<BR>\n" );
document.write( "(21X-28)/(X-6)(X+8)<BR>\n" );
document.write( "7X(3X-4)/(X-6)(X+8) ANS.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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