document.write( "Question 191991This question is from textbook Algebra I
\n" ); document.write( ": I am using the \"Glenco mathmatics Algebra 1\" book. I am doing extra practice in the back of the book in section 11-1. #24. The problem is using the process of simplifying radical expressions. \"square+root+of+27p%5E4%2F3p%5E2\" \n" ); document.write( "
Algebra.Com's Answer #144061 by jim_thompson5910(35256)\"\" \"About 
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\"sqrt%28%2827p%5E4%29%2F%283p%5E2%29%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%289p%5E2%29\" Divide \"%2827p%5E4%29%2F%283p%5E2%29\" to get \"9p%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%289%29%2Asqrt%28p%5E2%29\" Break up the square root using the identity \"sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Asqrt%28p%5E2%29\" Take the square root of \"9\" to get \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"3p\" Take the square root of \"p%5E2\" to get \"p\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%289%2Ap%5E2%29\" simplifies to \"3p\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%289%2Ap%5E2%29=3p\" where \"p%3E=0\".\r
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