document.write( "Question 191905: A rectangular patio is 7 ft longer than it is wide. Determine the dimensions of the patio if it measures 13 ft diagonally. \n" ); document.write( "
Algebra.Com's Answer #144010 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! x^2+(x+7)^2=13^2 \n" ); document.write( "x^2+x^2+14x+49=169 \n" ); document.write( "2x^2+14x+49-169=0 \n" ); document.write( "2x^2+14x-120=0 \n" ); document.write( "2(x^2+7x-60)=0 \n" ); document.write( "2(x-5)(x+12)=0 \n" ); document.write( "x-5=0 \n" ); document.write( "x=5 ans. for the length. \n" ); document.write( "x+7=12 ans. for the width. \n" ); document.write( "Proof: \n" ); document.write( "5^2+12^2=13^2 \n" ); document.write( "25+144=169 \n" ); document.write( "169=169 \n" ); document.write( " |