document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191935>Question 191935</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321233832/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> How are addition and multiplication used to solve a linear equation?  Demonstrate by solving \"12x + 6 = 31 – 2x\"  Thank You! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144009 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve a linear equation, isolate the unknown to one side of the equat<BR>\n" );
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document.write( "12x + 6 = 31 – 2x<BR>\n" );
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document.write( "Start by moving all the x terms to the left.  Do this by ADDING 2x to both sides:<BR>\n" );
document.write( "12x + 6 + 2x = 31 – 2x + 2x<BR>\n" );
document.write( "14x + 6 = 31<BR>\n" );
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document.write( "Next, subtract 6 from both sides:<BR>\n" );
document.write( "14x + 6 - 6 = 31 - 6<BR>\n" );
document.write( "14x = 25<BR>\n" );
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document.write( "Finally, MULTIPLY both sides by (1/14):<BR>\n" );
document.write( "(1/14)14x = 25(1/14)<BR>\n" );
document.write( "x = 25/14 (solution for x)\r<BR>\n" );
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