document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191906>Question 191906</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three consecutive even integers are such that the square of the third is 100 more than the square of the second. Find the three integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144008 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144008\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x, (x+2) & (x+4) be the three consecutive even integers.<BR>\n" );
document.write( "(x+4)^2=(x+2)^2+100<BR>\n" );
document.write( "x^2+8x+16=x^2+4x+4+100<BR>\n" );
document.write( "x^2-x^2+8x-4x=100+4-16<BR>\n" );
document.write( "4x=88<BR>\n" );
document.write( "x=88/4<BR>\n" );
document.write( "x=22 ans. for the first integer.<BR>\n" );
document.write( "22+2=24 for the middle integer.<BR>\n" );
document.write( "22+4=26 for the third integer.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "26^2=24^2+100<BR>\n" );
document.write( "676=576+100<BR>\n" );
document.write( "676=676 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );