document.write( "Question 191931: The area of a rectangle is 64cm^2. Its length is 4times the width. What is its length and width? THANK YOU TO WHO EVER HELPS ME WITH THIS. THANK YOU THANK YOU THANK YOU. \n" ); document.write( "

Algebra.Com's Answer #144000 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Start with the formula for the area of a rectangle:
\n" ); document.write( " $\"A+=+L%2AW\"$
\n" ); document.write( "Now since you are given that the length (L) is four times the width (W), and that the area (A) is 64 sq.cm., you can substitute $\"A+=+64\"$ and $\"L+=+4W\"$ in the formula for the area:
\n" ); document.write( " $\"64+=+%284W%29W\"$ Simplifying this, we get:
\n" ); document.write( " $\"64+=+4W%5E2\"$ Divide both sides by 4.
\n" ); document.write( " $\"16+=+W%5E2\"$ Take the square root of both sides.
\n" ); document.write( " $\"4+=+W\"$ N.B. We use only the positive solution of the square root because the width (W) is a positive quantity.
\n" ); document.write( "So the width is 4 cm. and the length L = 4W, so:
\n" ); document.write( " $\"L+=+16\"$
\n" ); document.write( "The length is 16 cm. \n" ); document.write( "

\n" );