document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26531>Question 26531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Car A leaves sacramento at noon traveling at 60 mph on road 560 miles long to Los Angeles. Car B leaves Los Angeles at 2 pm traveling at constant speed along the smae road  to Sacramento. They meet at 6 pm. What was the speed of car B? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14400 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since they meet together at same distacne; the distance is 560miles.<BR>\n" );
document.write( "Let the speed of the car B be x<BR>\n" );
document.write( "Together x+60=560. Now the times for car a is 6h total and the time for car b is 4 hours total.<BR>\n" );
document.write( "Car a = 6(60)<BR>\n" );
document.write( "car b = 4(x)<BR>\n" );
document.write( "together = 560 miles<BR>\n" );
document.write( "4(x)+6(60)=560<BR>\n" );
document.write( "4x+360=560<BR>\n" );
document.write( "4x=200<BR>\n" );
document.write( "x=50\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( "Hence, the speed for car B is 50mph.<BR>\n" );
document.write( "Paul.<BR>\n" );
document.write( " </SPAN>\n" );
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