document.write( "Question 191854: The Lang family and the Rogers family went to a brunch buffet. The restaurant charges one price for adults and another price for children. The Lang family has two adults and three children, and their bill was $40.50. The Rogers family has three adults and one child, and their bill was $38.00. What is the price of the buffet for an adult and the price of a child? \n" ); document.write( "
Algebra.Com's Answer #143957 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! Let A = adult price \n" ); document.write( "let C = Child price\r \n" ); document.write( "\n" ); document.write( "1) 2A+3C=40,5\r \n" ); document.write( "\n" ); document.write( "2) 3A+1C=38.00\r \n" ); document.write( "\n" ); document.write( "mult (2) by 3\r \n" ); document.write( "\n" ); document.write( "9A+3C=114.00\r \n" ); document.write( "\n" ); document.write( "subtract (1)\r \n" ); document.write( "\n" ); document.write( "7A +0C= 73.50 \n" ); document.write( "divide by 7, both sides of eqn\r \n" ); document.write( "\n" ); document.write( "A=10.50\r \n" ); document.write( "\n" ); document.write( "subst in (1)\r \n" ); document.write( "\n" ); document.write( "2(10.5) + 3C = 40,50 \n" ); document.write( "21.00 +3C= 40.50\r \n" ); document.write( "\n" ); document.write( "subtract 21.00 both sides\r \n" ); document.write( "\n" ); document.write( "3C= 19.50 \n" ); document.write( "divide both sides by 3\r \n" ); document.write( "\n" ); document.write( "C=6.50\r \n" ); document.write( "\n" ); document.write( "check\r \n" ); document.write( "\n" ); document.write( "2(10,50) + 3(6.50)= 21 + 19.50 = 40.50 ok\r \n" ); document.write( "\n" ); document.write( "3(10.50) + 6.50 = 31.50 + 6.50 = 38.00 ok \n" ); document.write( " |