document.write( "Question 191854: The Lang family and the Rogers family went to a brunch buffet. The restaurant charges one price for adults and another price for children. The Lang family has two adults and three children, and their bill was $40.50. The Rogers family has three adults and one child, and their bill was $38.00. What is the price of the buffet for an adult and the price of a child? \n" ); document.write( "
Algebra.Com's Answer #143953 by checkley75(3666)\"\" \"About 
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2A+3C=40.50
\n" ); document.write( "3A+C=38.00 OR C=38.00-3A
\n" ); document.write( "NOW REPLACE C WITH (38.00-3A) IN THE FIRST EQUATION & SOLVE FOR A.
\n" ); document.write( "2A+3(38.00-3A)=40.50
\n" ); document.write( "2A+114.00-9A=40.50
\n" ); document.write( "-7A=40.50-114.00
\n" ); document.write( "-7A=-73.50
\n" ); document.write( "A=-73.50/-7
\n" ); document.write( "A=10.50 IS THE PRICE FOR EAXH ADULT.
\n" ); document.write( "2*10.50+3C=40.50
\n" ); document.write( "21.00+3C=40.50
\n" ); document.write( "3C=40.50-21.00
\n" ); document.write( "3C=19.50
\n" ); document.write( "C=19.50/3
\n" ); document.write( "C=6.50 IS THE PRICE FOR EACH CHILD.
\n" ); document.write( "PROOF:
\n" ); document.write( "3*10.50+6.50=38.00
\n" ); document.write( "31.50+6.50=38.00
\n" ); document.write( "38.00=38.00\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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