document.write( "Question 191845: how can the number 45 be divided into two parts so that 4 times one part is 9 less than 5 times the other? \n" ); document.write( "

Algebra.Com's Answer #143950 by nerdybill(7384) $\"\"$ $\"About$

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how can the number 45 be divided into two parts so that 4 times one part is 9 less than 5 times the other?
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\n" ); document.write( "Let x = first part
\n" ); document.write( "then
\n" ); document.write( "45-x = second part
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\n" ); document.write( "4(45-x) = 5x-9
\n" ); document.write( "180 - 4x = 5x-9
\n" ); document.write( "180 = 9x-9
\n" ); document.write( "189 = 9x
\n" ); document.write( "21 = x (first part)
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\n" ); document.write( "Second part:
\n" ); document.write( "45-x = 45-21 = 24 (second part) \n" ); document.write( "

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