document.write( "Question 191520: Given the surface area of a sphere is 40 pi cm^2, find its volume. \r
\n" );
document.write( "\n" );
document.write( "And given that the area of an equilateral triangle is 67 cm^2, find its perimeter. \n" );
document.write( "
Algebra.Com's Answer #143943 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Given the surface area of a sphere is 40 pi cm^2, find its volume. \n" ); document.write( ": \n" ); document.write( "Two formulas: V = \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Divide both sides by 4pi \n" ); document.write( "r^2 = 10 \n" ); document.write( "r = \n" ); document.write( "Find the Volume \n" ); document.write( "V = \n" ); document.write( "V = 132.46 cu/cm \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "And given that the area of an equilateral triangle is 67 cm^2, find its perimeter. \n" ); document.write( "; \n" ); document.write( "Let x = the side of the triangle; \n" ); document.write( "Find the height: \n" ); document.write( "h = \n" ); document.write( "h = \n" ); document.write( "Find x using the area: \n" ); document.write( " \n" ); document.write( "Multiply both sides by 2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x^2 = 154.73 \n" ); document.write( "x = \n" ); document.write( "x = 12.44 \n" ); document.write( ": \n" ); document.write( "P = 3(12.44) \n" ); document.write( "P = 37.3 cm\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |