document.write( "Question 191520: Given the surface area of a sphere is 40 pi cm^2, find its volume. \r
\n" ); document.write( "\n" ); document.write( "And given that the area of an equilateral triangle is 67 cm^2, find its perimeter.
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Algebra.Com's Answer #143943 by ankor@dixie-net.com(22740)\"\" \"About 
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Given the surface area of a sphere is 40 pi cm^2, find its volume.
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\n" ); document.write( "Two formulas: V = \"%284%2F3%29%2Api%2Ar%5E3\" & SA = \"4%2Api%2Ar%5E2\"
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\n" ); document.write( "\"4%2Api%2Ar%5E2\" = 40*pi
\n" ); document.write( "Divide both sides by 4pi
\n" ); document.write( "r^2 = 10
\n" ); document.write( "r = \"sqrt%2810%29\"
\n" ); document.write( "Find the Volume
\n" ); document.write( "V = \"%284%2F3%29%2Api%2A%28sqrt%2810%29%29%5E3\"
\n" ); document.write( "V = 132.46 cu/cm
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\n" ); document.write( "And given that the area of an equilateral triangle is 67 cm^2, find its perimeter.
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\n" ); document.write( "Let x = the side of the triangle;
\n" ); document.write( "Find the height:
\n" ); document.write( "h = \"sqrt%28x%5E2+-+%28.5x%29%5E2%29\"
\n" ); document.write( "h = \"sqrt%28.75x%5E2%29\"
\n" ); document.write( "Find x using the area:
\n" ); document.write( "\"%281%2F2%29%2Ax%2Asqrt%28.75x%5E2%29\" = 67
\n" ); document.write( "Multiply both sides by 2
\n" ); document.write( "\"x%2Asqrt%28.75x%5E2%29\" = 134
\n" ); document.write( "\"x%2Ax%2Asqrt%28.75%29\" = 134
\n" ); document.write( "\"x%5E2%2Asqrt%28.75%29\" = 134
\n" ); document.write( "\"x%5E2\" = \"134%2F%28sqrt%28.75%29%29\"
\n" ); document.write( "x^2 = 154.73
\n" ); document.write( "x = \"sqrt%28154.73%29\"
\n" ); document.write( "x = 12.44
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\n" ); document.write( "P = 3(12.44)
\n" ); document.write( "P = 37.3 cm\r
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