document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191791>Question 191791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rhombus is 10 cm an measured angle A is 60 degrees. Find the length of the longer diagonal AC. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143934 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> RHOMBUS  =  ALL  SIDES  EQUAL\r<BR>\n" );
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document.write( "             f ----d.................................c<BR>\n" );
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document.write( "            a....................................b---e\r<BR>\n" );
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document.write( "Let  abcd  be  rhombus<BR>\n" );
document.write( "angle  dcb  =  60  deg<BR>\n" );
document.write( "therefore  angle  bcd  =60,  angle  bce  =  30  deg\r<BR>\n" );
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document.write( "bce  is  a  30 - 60 - 90  right  triangle\r<BR>\n" );
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document.write( "bc  =10   (given)<BR>\n" );
document.write( "be  =  5  (given  1/2  of  bc  due  to  30-60-90  proportions)\r<BR>\n" );
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document.write( "ce =  5sq rt 3  (  given  30-60-90  proportions\r<BR>\n" );
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document.write( "triangle  ae-ce-ca  is  rt  triangle  with  sides  (10 +5 =15) - (5 sq rt 3) - diagonal (ac)\r<BR>\n" );
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document.write( "using  pythagorous      c^2 = a^2 = b^2\r<BR>\n" );
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document.write( "(ac)^2  =  (ae)^2 + (ce)^2<BR>\n" );
document.write( "ac^2 =  15^2 + (5sq rt 3)^2<BR>\n" );
document.write( "ac^2 =  225 + (25*3)<BR>\n" );
document.write( "ac^2 = 300<BR>\n" );
document.write( "ac = sq rt 300 =  10 sq rt 3\r<BR>\n" );
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document.write( "short  diagonal  is  bd = 5 sq rt 7  in  similar  fashion\r<BR>\n" );
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document.write( "bd^2= 10^2 + ( 5sq rt 3)^2 = 175 </SPAN>\n" );
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