document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191761>Question 191761</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me solve this equation...\r<BR>\n" );
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document.write( "10r-9s=18<BR>\n" );
document.write( "6s+2r=1\r<BR>\n" );
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document.write( "its either a substitution problem or you add or subtract..\r<BR>\n" );
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document.write( "i have tried and tried to get this answer but i can't seem to get it..\r<BR>\n" );
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document.write( "thank you so much for helping! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143874 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143874\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)   10R-9S  =  18\r<BR>\n" );
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document.write( "2)   2R  +6S  =1\r<BR>\n" );
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document.write( "mult  (2)  by  5\r<BR>\n" );
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document.write( "2a)   10R  +30S  =5\r<BR>\n" );
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document.write( "subst ( 2a)  from  (1)\r<BR>\n" );
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document.write( "-39S =13\r<BR>\n" );
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document.write( "S=  -1/3\r<BR>\n" );
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document.write( "subst  in  (2)\r<BR>\n" );
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document.write( "2R  + 6(-1/3)  =  1\r<BR>\n" );
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document.write( "2R  -2  =1\r<BR>\n" );
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document.write( "2R = 3\r<BR>\n" );
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document.write( "R=3/2\r<BR>\n" );
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document.write( "check\r<BR>\n" );
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document.write( "6(-1/3) + 2 ( 3/2)  = 1<BR>\n" );
document.write( "-2  +3  =1    ok\r<BR>\n" );
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document.write( "10 (3/2) -9(-1/3)  =18<BR>\n" );
document.write( "15 +3 = 18  ok </SPAN>\n" );
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