document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26520>Question 26520</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a triangle is 32 centimeters.  The first side is 3cm longer than the second side, and the third side is 6 cm shorter than three times the second side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14387 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LEt the second side be x<BR>\n" );
document.write( "Let the first side be x+3<BR>\n" );
document.write( "Let the third side be 3x-6<BR>\n" );
document.write( "Perimeter = 32<BR>\n" );
document.write( "(x)+(x+3)+(3x-6)=32<BR>\n" );
document.write( "5x-3=32<BR>\n" );
document.write( "5x=35<BR>\n" );
document.write( "x=7 (second side)\r<BR>\n" );
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document.write( "7+3=10 (first side)<BR>\n" );
document.write( "3(7)-6=15 (third side)\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( "Hence, the three sides, are 7cm, 10cm, and 15cm.<BR>\n" );
document.write( "PAUL. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );