document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191760>Question 191760</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the problem is: \r<BR>\n" );
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document.write( "3a-4b=1<BR>\n" );
document.write( "12a-b= -11\r<BR>\n" );
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document.write( "this is as far as i have gotten...\r<BR>\n" );
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document.write( " 3a-4b=1<BR>\n" );
document.write( " 4(12a-b= -11)<BR>\n" );
document.write( "________________<BR>\n" );
document.write( "  3a-4b=1<BR>\n" );
document.write( "_  48a-4b= -44<BR>\n" );
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document.write( "45a= -43\r<BR>\n" );
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document.write( "then i don't know.. i have to solve for a and b\r<BR>\n" );
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document.write( "thank you so much for helping me!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143868 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)  3a  -4b  =  1<BR>\n" );
document.write( "2)  12a  - b = -11\r<BR>\n" );
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document.write( "mult  (2)  by  4\r<BR>\n" );
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document.write( "2a)  48a  -4b  =  -44\r<BR>\n" );
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document.write( "subst  (1)   from  (2a)\r<BR>\n" );
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document.write( "45a  =  -45\r<BR>\n" );
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document.write( "a  =   (-1)\r<BR>\n" );
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document.write( "subst  in  (1)   \r<BR>\n" );
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document.write( "3(-1)  -  4b  =  1\r<BR>\n" );
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document.write( "-3  -4b  =1\r<BR>\n" );
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document.write( "-4 =  4b\r<BR>\n" );
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document.write( "b=  (-1)\r<BR>\n" );
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document.write( "check\r<BR>\n" );
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document.write( "3 (-1)  - 4(-1)  =1<BR>\n" );
document.write( "1  =1      ok\r<BR>\n" );
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document.write( "12(-1)  -  (-1)  =  -11\r<BR>\n" );
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document.write( "-11  =  -11  ok </SPAN>\n" );
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