document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191752>Question 191752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is there some way someone can help me with this? I get lost after the first sentence.<BR>\n" );
document.write( "A disk jockey must play 14 commercial spots during one hour of a radio show. Each commercial is either 30 seconds or 60 seconds long. If the total commercial time during 1 hour is 11 minutes, how many 60 second commercials were played that hour.                                                         I thank you.very much, kate  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143862 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let  14  =  total  comm  spots\r<BR>\n" );
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document.write( "let  x  =  #  of  30  sec spots,  therefore  14-x =  #  of  60  sec spots\r<BR>\n" );
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document.write( "total  comm  time  is  11  min  =  11 *60  sec  =  660  sec\r<BR>\n" );
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document.write( "total  time   =  30  x  +  60 ( 14-x)  =  660\r<BR>\n" );
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document.write( "simplifying      30 x  -60  x  +  840  =  660\r<BR>\n" );
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document.write( "                         -30x  =  - 180\r<BR>\n" );
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document.write( "                               x=6    (  #  of  30  sec  spots)\r<BR>\n" );
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document.write( "                              and  (14-x)  =  14-6 = 8   (#  0f  60  sec  spots)\r<BR>\n" );
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document.write( "check    (6) (30)  + (8)  (60)  =  660  sec  =  11  min  ok </SPAN>\n" );
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