document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191742>Question 191742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In triangleABC measure of angle A=30 degrees and measure of angle C=90 degrees. If the length of BC is four more than one-fourth of AB, find the length of the longer leg of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143861 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> draw  triangle  abc\r<BR>\n" );
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document.write( "a=30deg,   c=90  deg,  therefore  b=60  deg   (sum  of  angles  =  180)\r<BR>\n" );
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document.write( "bc  =  .25 ab  +4     (given)\r<BR>\n" );
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document.write( "but  in  30-60-90  triangle,    bc  =  1/2  ab\r<BR>\n" );
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document.write( "therefore  ab  =  1/2  ab  +8\r<BR>\n" );
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document.write( "simplifying    1/2  ab  =  8\r<BR>\n" );
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document.write( "ab=16\r<BR>\n" );
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document.write( "subst  bc  =  .25  (16)  +4  =  8\r<BR>\n" );
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document.write( "using  pythagorous  \r<BR>\n" );
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document.write( "16^2  - 8^2  =  256 - 64 =  192 =  ac^2\r<BR>\n" );
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document.write( "ac =  (64  *3)^.5  =  8 *3^.5   or  8  sq rt  3\r<BR>\n" );
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document.write( "check   30-60-90  triangle  makes  1-2-sq rt 3  sides,  8-16-8sqrt3  ok </SPAN>\n" );
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