document.write( "Question 191730: Hi there, I just can't get this type of problem so I need some help. If anyone would like to solve this, I would be very greatful.
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document.write( "The perimeter of a rectangle is 132 inches. The length exceeds the width by 58 inches. Find the length and width in inches. \n" );
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Algebra.Com's Answer #143847 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! let L and W be the length and width of rectangle respectively \n" ); document.write( ": \n" ); document.write( "P=132............eq 1 \n" ); document.write( "P=2L+2W..........eq 2 \n" ); document.write( "L=W+58...........eq 3 \n" ); document.write( ": \n" ); document.write( "take P's value from eq 2 and L's value from eq 3 and plug them into eq 1 \n" ); document.write( ": \n" ); document.write( "132=2(W+58)+2W \n" ); document.write( ": \n" ); document.write( "132=2W+116+2W \n" ); document.write( ": \n" ); document.write( "16=4W \n" ); document.write( ": \n" ); document.write( "W=4 \n" ); document.write( ": \n" ); document.write( "L=W+58=4+58=62 \n" ); document.write( " \n" ); document.write( " |