document.write( "Question 191730: Hi there, I just can't get this type of problem so I need some help. If anyone would like to solve this, I would be very greatful.
\n" ); document.write( "The perimeter of a rectangle is 132 inches. The length exceeds the width by 58 inches. Find the length and width in inches.
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Algebra.Com's Answer #143847 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
let L and W be the length and width of rectangle respectively
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\n" ); document.write( "P=132............eq 1
\n" ); document.write( "P=2L+2W..........eq 2
\n" ); document.write( "L=W+58...........eq 3
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\n" ); document.write( "take P's value from eq 2 and L's value from eq 3 and plug them into eq 1
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\n" ); document.write( "132=2(W+58)+2W
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\n" ); document.write( "132=2W+116+2W
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\n" ); document.write( "16=4W
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\n" ); document.write( "W=4
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\n" ); document.write( "L=W+58=4+58=62
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