document.write( "Question 191731This question is from textbook
\n" ); document.write( ": Three consecutive even integers are such that the square of the third is 100 more than the square of the second. Find 3 integers. I am sooo lost.
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Algebra.Com's Answer #143836 by ankor@dixie-net.com(22740)\"\" \"About 
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Three consecutive even integers: x, (x+2), (x+4)
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\n" ); document.write( "the square of the third is 100 more than the square of the second.
\n" ); document.write( "(x+4)^2 = (x+2)^2 + 100
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 + 8x + 16 = x^2 + 4x + 4 + 100
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\n" ); document.write( "x^2 + 8x + 16 = x^2 + 4x + 104
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\n" ); document.write( "Arrange the x's on the left, numbers on the right:
\n" ); document.write( "x^2 - x^2 + 8x - 4x = 104 - 16
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\n" ); document.write( "4x = 88
\n" ); document.write( "x = \"88%2F4\"
\n" ); document.write( "x = 22, 24, 26; are the numbers
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"the square of the third is 100 more than the square of the second.\"
\n" ); document.write( "26^2 = 24^2 + 100
\n" ); document.write( "676 = 576 + 100
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