document.write( "Question 191668: I need your help in how to solve the question\r
\n" );
document.write( "\n" );
document.write( "Solve over the interval [0,360]\r
\n" );
document.write( "\n" );
document.write( "sin 2x = cos 2x +1 \n" );
document.write( "
Algebra.Com's Answer #143792 by J2R2R(94) You can put this solution on YOUR website! Sin 2x = Cos 2x + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 Sin x Cos x = Cos 2x + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 Sin x Cos x = Cos^2 x – Sin^2 x + Cos^2 x + Sin^2 x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 Sin x Cos x = 2 Cos^2 x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cancel out the 2 Cos x (giving solutions for Cos x = 0 are 90 and 270)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sin x = Cos x gives solutions 45 and 225\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore the solutions are 45, 90, 225 and 270 degrees. \n" ); document.write( " |