document.write( "Question 191662: logx(1/16)=-4\r
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document.write( "the log x, the x is suppose to be under the log. \r
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document.write( "here are the choices:
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document.write( "a. 2
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document.write( "b. 1/4
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document.write( "c. 4
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document.write( "d. 1/2
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Algebra.Com's Answer #143791 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "logx(1/16)=-4 \n" ); document.write( "1/16 = x^(-4) \n" ); document.write( "1/16 = 1/x^4 \n" ); document.write( "Cross multiplying: \n" ); document.write( "x^4 = 16 \n" ); document.write( "x = fourth root (6) \n" ); document.write( "x = 2 \n" ); document.write( ". \n" ); document.write( "Answer: a \n" ); document.write( " \n" ); document.write( " |