document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191655>Question 191655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square. First divide to make sure that the coefficient of x^2 is 1\r<BR>\n" );
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document.write( "9x^2+18x=-8\r<BR>\n" );
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document.write( "I completed the square but dividing to make sure that the coefficient is 1 I am not understanding. Here is what I did...<BR>\n" );
document.write( "9x^2+18x+8=0<BR>\n" );
document.write( "(3x+4)(3x+2)<BR>\n" );
document.write( "3x+4=0   3x+2=0<BR>\n" );
document.write( "3x=-4    3x=-2<BR>\n" );
document.write( "x=-4/3   x=-2/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143787 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Although your answer is correct, you solved it by factoring instead of \"completing the square\".<BR>\n" );
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document.write( "9x^2+18x=-8 <BR>\n" );
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document.write( "9(x^2+2x) = -8 <BR>\n" );
document.write( "9(x^2+2x+__) = -8 <BR>\n" );
document.write( "Take half the 'b' term and square it.  Then balance the right with what you just added to the left side.<BR>\n" );
document.write( "9(x^2+2x+1) = -8 + 9<BR>\n" );
document.write( "9(x+1)^2 = 1<BR>\n" );
document.write( "Dividing both sides by 9:<BR>\n" );
document.write( "(x+1)^2 = 1/9<BR>\n" );
document.write( "Taking the square root of both sides:<BR>\n" );
document.write( "(x+1) = +-(1/3) (that's plus or minus 1/3)<BR>\n" );
document.write( "x = +-(1/3) - 1<BR>\n" );
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document.write( "x = 1/3 - 1 = 1/3 - 3/3 = -2/3<BR>\n" );
document.write( "x = -1/3 - 1 = -1/3 - 3/3 = -4/3<BR>\n" );
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document.write( "x = {-4/3, -2/3}\r<BR>\n" );
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