document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191537>Question 191537</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0028253221/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Hi.<BR>\n" );
document.write( "In this question it asks for AB to be found.<BR>\n" );
document.write( "It is a circle with the center point P. It has a radius of 6 and a chord AB drawn from one point to another. The chord divides the circle into a certain section and it has an arch that on the outside of it it says 120 degrees. <BR>\n" );
document.write( "The radius is not drawn horizontally, but if it was drawn horizontally it would still be 6 and would seem to bisect the chord and then create a right triangle onto which the Pythagorean theorem could be used to find 1/2 of AB.\r<BR>\n" );
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document.write( "Thanks for your time! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143784 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a  sketch  would  help  but  bear  with  me\r<BR>\n" );
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document.write( "arc  =  120  deg  means  that  central  angle  bpa  =  120  deg\r<BR>\n" );
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document.write( "now  you  can  do  the  triangle  resolution  as  you  suggested\r<BR>\n" );
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document.write( "angle  pab  is  now  30  deg     (  (180-120)  /2  )  \r<BR>\n" );
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document.write( "pa  is  radius  =6\r<BR>\n" );
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document.write( "1/2  of  ba  is   sq  rt  of  (6^2 -3^2 )  =  5.196\r<BR>\n" );
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document.write( "ba  is  10.392\r<BR>\n" );
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document.write( "check  sin  60  deg  =  5.196 / 6  =  ,866        ok </SPAN>\n" );
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