document.write( "Question 191642: Andrea can rake her Dad's yard in 45 minutes. Andrea's brother Bradford rakes one and one-half times faster than Andrea. How long would it take them to rake their Dad's yard together? \n" ); document.write( "
Algebra.Com's Answer #143778 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x=amount of time it takes them to rake their dad's yard together
\n" ); document.write( "So, together they rake the yard at the rate of 1/x yard per min
\n" ); document.write( "Andrea rakes the yard at the rate of 1/45 yard per min
\n" ); document.write( "Then Bradford rakes at the rate of (1.5)*(1/45)=(3/2)(1/45)=3/90=1/30 yard per min
\n" ); document.write( "Now our equation to solve is
\n" ); document.write( "1/45 +1/30 = 1/x multiply each term by 180x
\n" ); document.write( "4x+6x=180 collect like terms
\n" ); document.write( "10x=180
\n" ); document.write( "x=18 min-------------------amount of time it takes them to rake their dad's yard together\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "In 18 min Andrea can do (1/45)*18=18/45=2/5 of the lawn
\n" ); document.write( "In 18 min, Bradford can do (1/30)*18=18/30=3/5 of the lawn
\n" ); document.write( "2/5 +3/5 =5/5 (the whole lawn)\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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