document.write( "Question 191641: A large pump can filla 77,000 gallon reservoir in 7 hours. Working together, the large pump and a smaller one can fill the reservoir in 6 hours. How long would it take the smaller pump to fill the reservoir by itself? \n" ); document.write( "

Algebra.Com's Answer #143771 by orca(409) $\"\"$ $\"About$

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Let x represent the amount of water the smaller pump can pump per hour.\r
\n" ); document.write( "\n" ); document.write( "The amount of water the larger pump can pump per hour is 77000/7 = 11000 gallons/h.\r
\n" ); document.write( "\n" ); document.write( "Working together the number of gallons of water they can pump each hour is
\n" ); document.write( "11000 + x.\r
\n" ); document.write( "\n" ); document.write( "As they can fill the reservoir in 6 hours, we have
\n" ); document.write( "6(11000+x)=77000
\n" ); document.write( "Solving for x, we have
\n" ); document.write( "11000 + x = 77000/6
\n" ); document.write( "x = 77000/6-11000
\n" ); document.write( "x = 77000/6-66000/6 = 11000/6\r
\n" ); document.write( "\n" ); document.write( "Therefore the amount of water the smaller pump can pump per hour is 11000/6.\r
\n" ); document.write( "\n" ); document.write( "So the time it takes for the smaller pump to fill the reservoir is\r
\n" ); document.write( "\n" ); document.write( " $\"77000%2F%2811000%2F6%29=+77000%2A6%2F11000=+42\"$ hours.\r
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