document.write( "Question 191608This question is from textbook
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document.write( ": I need help with this problem, I am taking elementary algebra in college.
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document.write( "Jake borrowed $5000 from two different banks. One bank charges 7% simple interest, and other charges 8.5% simple interest. If the total interest payment is $380, how much did he borrow? \n" );
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Algebra.Com's Answer #143747 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! let x and y be the amounts borrowed at 7% and 8.5 % interest respectively \n" ); document.write( ": \n" ); document.write( "x+y=5000..........eq1 \n" ); document.write( ".07x+.085y=380....eq 2 \n" ); document.write( ": \n" ); document.write( "rewrite eq 1 to x=5000-y and plug this value into eq 2 \n" ); document.write( ": \n" ); document.write( ".07(5000-y)+.085y=380 \n" ); document.write( ": \n" ); document.write( "350-.07y+.085y=380 \n" ); document.write( ": \n" ); document.write( ".015y=30 \n" ); document.write( ": \n" ); document.write( "y=2000 dollars at 8.5% \n" ); document.write( ": \n" ); document.write( "x=5000-y=5000-2000=3000 dollars at 7% \n" ); document.write( " |