document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191436>Question 191436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 100-foot vertical tower is to be erected on the side of a hill that makes a 6* angle with the horizontal. Find the length of each of the two guy wires that will be anchored 75 feet uphill and downhill from the base of the tower. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143730 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 100-foot vertical tower is to be erected on the side of a hill that makes<BR>\n" );
document.write( " a 6* angle with the horizontal. <BR>\n" );
document.write( "Find the length of each of the two guy wires that will be anchored 75 feet<BR>\n" );
document.write( " uphill and downhill from the base of the tower.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Treat this as two different triangles;<BR>\n" );
document.write( "The uphill triangle: A= 90-6 = 84 degrees<BR>\n" );
document.write( "Use the law of cosines: a^2 = b^2 + c^2 - 2(a*b)cos(A)<BR>\n" );
document.write( "A = 84 degrees<BR>\n" );
document.write( "a = guy wire length<BR>\n" );
document.write( "b = 75'<BR>\n" );
document.write( "c = 100'<BR>\n" );
document.write( ":<BR>\n" );
document.write( "a^2 = 75^2 + 100^2 - 2(75*100)cos(84)<BR>\n" );
document.write( "a^2 = 5625 + 10000 - 2(7500)*.104528<BR>\n" );
document.write( "a^2 = 15625 - 1567.9<BR>\n" );
document.write( "a = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2814057%29 ALIGN=MIDDLE  ALT=\"sqrt%2814057%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = 118.56' length of the up-hill guy wire<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The down-hill triangle A = 90+6 = 96 degrees<BR>\n" );
document.write( "A = 96 degrees<BR>\n" );
document.write( "a = guy wire length<BR>\n" );
document.write( "b = 75'<BR>\n" );
document.write( "c = 100'<BR>\n" );
document.write( ":<BR>\n" );
document.write( "a^2 = 75^2 + 100^2 - 2(75*100)cos(96)<BR>\n" );
document.write( "a^2 = 5625 + 10000 - 2(7500)*-.1045<BR>\n" );
document.write( "a^2 = 15625 - (-1567.9)<BR>\n" );
document.write( "a^2 = 15625 + 1567.9<BR>\n" );
document.write( "a = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2817192.9%29 ALIGN=MIDDLE  ALT=\"sqrt%2817192.9%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = 131.12' length of the down-hill guy wire<BR>\n" );
document.write( ";<BR>\n" );
document.write( "I'll leave it up to you to check my math here.<BR>\n" );
document.write( " </SPAN>\n" );
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