document.write( "Question 191566: 4a+7b=22
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document.write( "8a+3c=7
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document.write( "6b+3c+3 \n" );
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Algebra.Com's Answer #143719 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 4a+7b=22 \n" ); document.write( "8a+3c=7 \n" ); document.write( "-(6b+3c=3) I'll assume the + should have been an = sign. Now subtract. \n" ); document.write( "-------- \n" ); document.write( "8a-6b=4 Now multiply the first equation by -2 & add. \n" ); document.write( "-8a-14b=-44 \n" ); document.write( "-------------- \n" ); document.write( "-20b=-40 \n" ); document.write( "b=-40/-20 \n" ); document.write( "b=2 ans. \n" ); document.write( "8a-6*2=4 \n" ); document.write( "8a-12=4 \n" ); document.write( "8a=4+12 \n" ); document.write( "8a=16 \n" ); document.write( "a=16/8 \n" ); document.write( "a=2 ans. \n" ); document.write( "6*2+3c=3 \n" ); document.write( "12+3c=3 \n" ); document.write( "3c=3-12 \n" ); document.write( "3c=-9 \n" ); document.write( "c=-9/3 \n" ); document.write( "c=-3 ans. \n" ); document.write( " |